(x+1/x)²-2=(√5-2+1/(√5-2))²-2=(√5-2+√5+2)²-2,你这个过程我看不太懂啊,求赐教!
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![(x+1/x)²-2=(√5-2+1/(√5-2))²-2=(√5-2+√5+2)²-2,你这个过程我看不太懂啊,求赐教!](/uploads/image/z/4327985-65-5.jpg?t=%28x%2B1%2Fx%29%26%23178%3B-2%3D%28%E2%88%9A5-2%2B1%2F%28%E2%88%9A5-2%29%29%26%23178%3B-2%3D%28%E2%88%9A5-2%2B%E2%88%9A5%2B2%29%26%23178%3B-2%2C%E4%BD%A0%E8%BF%99%E4%B8%AA%E8%BF%87%E7%A8%8B%E6%88%91%E7%9C%8B%E4%B8%8D%E5%A4%AA%E6%87%82%E5%95%8A%2C%E6%B1%82%E8%B5%90%E6%95%99%21)
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(x+1/x)²-2=(√5-2+1/(√5-2))²-2=(√5-2+√5+2)²-2,你这个过程我看不太懂啊,求赐教!
(x+1/x)²-2=(√5-2+1/(√5-2))²-2=(√5-2+√5+2)²-2,你这个过程我看不太懂啊,求赐教!
(x+1/x)²-2=(√5-2+1/(√5-2))²-2=(√5-2+√5+2)²-2,你这个过程我看不太懂啊,求赐教!
∵1/(√5-2)
=(√5+2)/(√5-2)(√5+2)
=(√5+2)/(5-4)
=√5+2;
(x+1/x)²-2
=(√5-2+1/(√5-2))²-2
=(√5-2+√5+2)²-2,
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,
(x+1/x)²-2
=[(√5-2)+1/(√5-2)]²-2
=[(√5-2)+(√5+2)/(√5-2)(√5+2)]²-2
=[(√5-2)+(√5+2)/(5-4)]²-2
=(√5-2+√5+2)²-2
=(2√5)²-2
=20-2
=18