若a²-5a-1=0,求(a-2)分之(a-2)的立方-(a-1)²+1的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/13 09:30:08
若a²-5a-1=0,求(a-2)分之(a-2)的立方-(a-1)²+1的值
x){ѽ4QMZ4Q@&D]#ͧmOvvg<_lN] P^(aMR>5/{@֨bR`U(ʠjUåN|am.)DF 1Q

若a²-5a-1=0,求(a-2)分之(a-2)的立方-(a-1)²+1的值
若a²-5a-1=0,求(a-2)分之(a-2)的立方-(a-1)²+1的值

若a²-5a-1=0,求(a-2)分之(a-2)的立方-(a-1)²+1的值
[(a-2)³-(a-1)²+1]/(a-2)
=[(a-2)³-a²+2a-1+1]/(a-2)
=[(a-2)³-a(a-2)]/(a-2)
=(a-2)²-a
=a²-4a+4-a
=a²-5a-1+5
=5