作业帮| 1/(x+1) |
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| 1/(x+1) |
| 1/(x+1) |
| 1/(x+1) |
左右同乘|x+1|
1
上式等价于|x+1|>=1。即：x+1>=1或x+1<=-1。所以x>=0或x<=-2
-1<1/(x+1)<1
X>0 或 x<-2
-1≤1/(x+1)≤1
1/(x+1)+1≥0 1/(x+1)-1≤0
(x+2)/(x+1)≥0 x/(x+1)≥0
x≤-2 OR x>-1 x≥0 OR x<-1
x≤-2 OR x≥0
两边平方得：｛1/（x＋1）｝≤1,①1/x＋1≤1.②1/x＋1≥－1.当①时，同时减去1，得1/(x＋1)－1≤0,即1/(x＋1)－(x＋1)/(x＋1)≤0,整理得－x/(x＋1)≤0，即－x(x＋1)≤0，解得x≤0或x≥1，当②时同理
这是一道比较典型的绝对值不等式与倒数不等式相结合的题目
由题设条件
去绝对值符号可以得到
-1<=1/(x+1)<= 1
再由倒数关系
则x+1>=1或
x+1<-1
即x>=0或x<=-2 是所求不等式的最终解
| 1/(x+1) | ≤ 1
-1≤ 1/(x+1) ≤ 1且x+1≠0 x≠-1
-1＜ 1/(x+1) ≤ 1
将两个不等式分开化简，同时乘以x+1,得
1≤x+1 x≥0
x<-2
所以x≥0 或x<-2
1/(x+1) <=1或1/(x+1) >=-1 x<=-2或x>=0
猪啊你
解:|1/(x+1)|<=1→1<=|x+1|→1<=x+1或x+1<=-1→0<=x 或x<=-2
所以x+1小于等于1，所以x小于等于0
x/x+(1-x)/x-1/x
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(x+1)(x-1)(x-x+1)(x+x+1)
分解因式----（X*X-X)(X*X-X-2)+1
X(X-1)=X
1.1/x|x/(x+1)|
x/x-1[1+(x-1/x)]
x-1/x÷(x-1/x)
】x(x+1)+x^2(x-1)
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
x>1/1-x
x+1/x-1
(X + 1) /(x - 1)
(1+X)/(1-X)
|x+1|+|x-1|
/X-3/-/X-1/