求∫(1+cos²x)/(1+cos2x) 求∫(1+cos²x)/(1+cos2x) dx=∫(1+cos²x)/(2cos²x) dx=(这等号这一部不懂.)x/2+(1/2)∫dx/cos²x=x/2+(tanx)/2+C
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求∫(1+cos²x)/(1+cos2x) 求∫(1+cos²x)/(1+cos2x) dx=∫(1+cos²x)/(2cos²x) dx=(这等号这一部不懂.)x/2+(1/2)∫dx/cos²x=x/2+(tanx)/2+C
求∫(1+cos²x)/(1+cos2x)
求∫(1+cos²x)/(1+cos2x) dx=∫(1+cos²x)/(2cos²x) dx=(这等号这一部不懂.)x/2+(1/2)∫dx/cos²x=x/2+(tanx)/2+C
求∫(1+cos²x)/(1+cos2x) 求∫(1+cos²x)/(1+cos2x) dx=∫(1+cos²x)/(2cos²x) dx=(这等号这一部不懂.)x/2+(1/2)∫dx/cos²x=x/2+(tanx)/2+C
cos2x=2cos^2x-1
所以
1+cos2x=2cos²x