（x+1)(x-3)(x+5)(x-7)+256

来源：学生作业帮助网编辑：作业帮时间：2024/11/05 13:37:30

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（x+1)(x-3)(x+5)(x-7)+256
（x+1)(x-3)(x+5)(x-7)+256

（x+1)(x-3)(x+5)(x-7)+256
（x+1)(x-3)(x+5)(x-7)+256
=(x²-2x-3)(x²-2x-35)+256
=(x²-2x)²-35(x²-2x)-3(x²-2x)+3×35+256
=(x²-2x)²-38(x²-2x)+361
=(x²-2x-19)²

　　（X+1)(X-3)(X+5)(X-7)+256

=(X^2-2X-3)(X^2-2X-35)+256
=(X^2-2X)^2-38(X^2-2X)+361
=(X^2-2X-19)^2

先将前后两项各自合并得到式-1，然后把其中的（X^2-2X ）作为一个整体在进行合并得到式-2，顺理成章就能得到式-3了

小凡，你是怎么用QQ号上百度的？？？

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