2x-3y+2z=1(x-1)/3=(y-3)/4=(z+2)/5
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2x-3y+2z=1(x-1)/3=(y-3)/4=(z+2)/5
2x-3y+2z=1
(x-1)/3=(y-3)/4=(z+2)/5
2x-3y+2z=1(x-1)/3=(y-3)/4=(z+2)/5
将z看成已知量,解以x,y为未知量的方程组,根据(x-1)/3=(z+2)/5可以求得x=(3z+11)/5,根据(y-3)/4=(z+2)/5可以求得y=(4z+23)/5,将求得的x,y代入2x-3y+2z=1 ,即得到一个只关于z的方程2(3z+11)/5-3(4z+23)/5+2z=1,求得z=13,即得x=10,y=15
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