(x^2-16/x^2+8x+16) + (x/x-4)
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(x^2-16/x^2+8x+16) + (x/x-4)
(x^2-16/x^2+8x+16) + (x/x-4)
(x^2-16/x^2+8x+16) + (x/x-4)
(x^2-16)/(x^2+8x+16)+ x/(x-4)
=(x-4)(x+4)/(x+4)^2+ x/(x-4)
=(x-4)/(x+4)+ x/(x-4)
=(x-4)^2/(x+4)(x-4)+ x(x+4)/(x-4)(x+4)
=[(x-4)^2+ x(x+4)]/(x-4)(x+4)
=(x^2-8x+16+x^2+4x)/(x-4)(x+4)
=(2x^2-4x+16)/(x-4)(x+4)
=2(x^2-2x+8)/(x-4)(x+4)
=2(x^2-2x+8)/(x^2-16)
=(x-4)(x+4)/(x+4)^2+ x/(x-4)
=(x-4)/(x+4)+ x/(x-4)
=(x-4)^2/(x+4)(x-4)+ x(x+4)/(x-4)(x+4)
=[(x-4)^2+ x(x+4)]/(x-4)(x+4)
=(x^2-8x+16+x^2+4x)/(x-4)(x+4)
=(2x^2-4x+16)/(x-4)(x+4)
=2(x^2-2x+8)/(x-4)(x+4)
=2(x^2-2x+8)/(x^2-16)
(x^2-16/x^2+8x+16) + (x/x-4)
=(x+4(x-4)/(x+4)^2+x/(x-4)
=(x-4)/(x+4)+x/(x-4)
=[(x-4)^2+x(x+4)]/[(x+4)(x-4)]
=(x^2-8x+4+x^2+4x)/[(x+4)(x-4)]
=(2x^2-4x+4)/(x^2-16)
(x^2-4x)/x^2-8x+16
通分:(1)2/x^2+x-2,1/x^2-2x-8(2)x/x^2-3x-4,1/x^2-8x+16
(x^2-16/x^2+8x+16) + (x/x-4)
x^2-8x+16分之x^2-4x
(x^2 + 4x)(x^2 + 4x+8)+16
(x^2-4x)(x^2-4x+8)+16
因式分解:(X+2)(X+4)(X+6)(X+8)+16
(16x^4+4x^2+x)/x=?
(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)
计算(x+/1x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)(x^16+1/x^16)(x^2-1)
(x+1/x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)(x^16+1/x^16)(x^2-1)
(x+x^-1)(x^2+x^-2)(x^4+x^-4)(x^8+x^-8)(x^16+x^-16)(x^2-1)=?
(x^2-8x+16)/(4-x^2)/(16-x^2)/(4+4x+x^2)
10x+2(x+4)=8x+16
x/x-2=x²-8x+16/x²²-4x+4
(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x-1)
x=1-x/2+x/4-x/8+x/16-x/32
X,2X,4X,8X,16X,32X,.第N个单项式为什么