如图,在三角形ABC中,角ACB=90度,角B=45度,且AC=BC,AD是BC边上的中线,过点C作AD的垂线交AB于点E,交AD于F,连结DE,则角ADC=角BDE,请说明理由.图有点不标准,请原谅,
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 17:59:58
![如图,在三角形ABC中,角ACB=90度,角B=45度,且AC=BC,AD是BC边上的中线,过点C作AD的垂线交AB于点E,交AD于F,连结DE,则角ADC=角BDE,请说明理由.图有点不标准,请原谅,](/uploads/image/z/4339227-3-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ACB%3D90%E5%BA%A6%2C%E8%A7%92B%3D45%E5%BA%A6%2C%E4%B8%94AC%3DBC%2CAD%E6%98%AFBC%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%BA%BF%2C%E8%BF%87%E7%82%B9C%E4%BD%9CAD%E7%9A%84%E5%9E%82%E7%BA%BF%E4%BA%A4AB%E4%BA%8E%E7%82%B9E%2C%E4%BA%A4AD%E4%BA%8EF%2C%E8%BF%9E%E7%BB%93DE%2C%E5%88%99%E8%A7%92ADC%3D%E8%A7%92BDE%2C%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1.%E5%9B%BE%E6%9C%89%E7%82%B9%E4%B8%8D%E6%A0%87%E5%87%86%2C%E8%AF%B7%E5%8E%9F%E8%B0%85%2C)
xݒaOP
i--]ZhX{[6,K4u.3/v1}y{ZY>SuG<:dUPDdԬ"oG"dU*M^V
ROpRJZTQT"F:T$4"Q0)\9T%zB:Z/i9mm_qy#q{O*$k^^W*qk9
xPp0s.m6|C2.gC=ϼsI5Ͳk/(%(Y %
ā)%$)a0mY