当X=7,y=-7.求x(x+2y)减(x+1)的平方+2x的值
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当X=7,y=-7.求x(x+2y)减(x+1)的平方+2x的值
当X=7,y=-7.求x(x+2y)减(x+1)的平方+2x的值
当X=7,y=-7.求x(x+2y)减(x+1)的平方+2x的值
x(x+2y)减(x+1)的平方+2x
=x²+2xy-x²-2x-1+2x
=2xy-1
=2×7×(-7)-1
=-98-1
=-99
x(x+2y)减(x+1)的平方+2x
x²+2xy-x²-2x-1+2x
=2xy-1
=2×7×(-7)-1
= -98-1
= -99
x(x+2y)-(x+1)²+2x
=x²+2xy-x²-2x-1+2x
=2xy-1
将X=7,y=-7代入得
2*7*(-7)-1==-98-1=-99
(x(x+2y)减(x+1))的平方+2x=3263或x(x+2y)-((x+1)的平方+2x=-99