若二次函数f(x)=ax^2+bx+c(a≠0)满足f(x+1)-f(x)=2x且f(0)=1 (1)求f(x)解析式(2)若在区间[-1,1]上,不等式f(x)>2x+m恒成立,求实数m的取值范围.
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![若二次函数f(x)=ax^2+bx+c(a≠0)满足f(x+1)-f(x)=2x且f(0)=1 (1)求f(x)解析式(2)若在区间[-1,1]上,不等式f(x)>2x+m恒成立,求实数m的取值范围.](/uploads/image/z/4346054-62-4.jpg?t=%E8%8B%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%28x%29%3Dax%5E2%2Bbx%2Bc%28a%E2%89%A00%29%E6%BB%A1%E8%B6%B3f%28x%2B1%29-f%28x%29%3D2x%E4%B8%94f%EF%BC%880%EF%BC%89%3D1+%EF%BC%881%EF%BC%89%E6%B1%82f%EF%BC%88x%EF%BC%89%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%882%EF%BC%89%E8%8B%A5%E5%9C%A8%E5%8C%BA%E9%97%B4%5B-1%2C1%5D%E4%B8%8A%2C%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%88x%29%3E2x%2Bm%E6%81%92%E6%88%90%E7%AB%8B%2C%E6%B1%82%E5%AE%9E%E6%95%B0m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4.)
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