{[a^(2n+1)-6a^(2n)+9a^(2n-1)]/(a^2-9)}/[a^(n+1)+4a^(n)+4a^(n-1)]/(a^2-4).

来源：学生作业帮助网编辑：作业帮时间：2024/07/04 18:08:33

${[a^(2n+1)-6a^(2n)+9a^(2n-1)]/(a^2-9)}/[a^(n+1)+4a^(n)+4a^(n-1)]/(a^2-4).$

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{[a^(2n+1)-6a^(2n)+9a^(2n-1)]/(a^2-9)}/[a^(n+1)+4a^(n)+4a^(n-1)]/(a^2-4).
{[a^(2n+1)-6a^(2n)+9a^(2n-1)]/(a^2-9)}/[a^(n+1)+4a^(n)+4a^(n-1)]/(a^2-4).

{[a^(2n+1)-6a^(2n)+9a^(2n-1)]/(a^2-9)}/[a^(n+1)+4a^(n)+4a^(n-1)]/(a^2-4).
是不是漏了一对大括弧
{[a^(2n+1)-6a^(2n)+9a^(2n-1)]/(a^2-9)}/[a^(n+1)+4a^(n)+4a^(n-1)]/(a^2-4)
={a^(2n-1)*(a-3)^2/[(a+3)(a-3)]}/{a^(n-1)*(a+2)^2/[(a+2)(a-2)]}
=a^n*(a-3)(a-2)/[(a+3)(a+2)]

(3a^n+1+6a^n+2-9a^n)/3a^n-1 (6a^n+2 +3a^n+1 -9a^n)/3a^n-1 计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1 分式计算：a^(2n+1)-6a^(2n)+9a^(2n-1) / a^(n+1)-4a^n+3a^(n-1) （4a^2n-6a^n+1+2a^n)/2a^n 因式分解（6a^n+2+3a^n+1-9a^n)÷1/2a^n-1 计算(3a^n+1-6a^n+9a^n-1)/(1/3a^n-2) 计算：(6a^n+2-9a^n+1+3a^n-1)÷3a^n-1 (3a^（n+1）+6a^（n+2）-9a^n)/3a^（n-1）是计算 (3a^n+1+6a^n+2-9a^n)/3a^n-1是计算题设a,n∈N*证明a^2n-(-a)^n≥(a+1)×a^n 如果n是正整数,[(8a^n+3)-(6a^n+2)-(5a^n+1)]/(-a)^n a^n+1+a^n-1-2a^n因式分解 a^n+2+a^n+1-a^n因式分解 a^n+2+a^n+1-3a^n因式分解因式分解:a^n+2-6a^n (a^n+1)-(a^n-2)等于因式分解：9a^2+x^2n+6a+2x^n+6ax^n+1