求下面函数的定义域:y=根号下【(x-1)/(x+1)】+根号下(6-x-x^2)
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求下面函数的定义域:y=根号下【(x-1)/(x+1)】+根号下(6-x-x^2)
求下面函数的定义域:
y=根号下【(x-1)/(x+1)】+根号下(6-x-x^2)
求下面函数的定义域:y=根号下【(x-1)/(x+1)】+根号下(6-x-x^2)
首先,(x-1)/(x+1)要大于等于0,同理,6-x-x^2也要大于等于0
1.当,(x-1)/(x+1)要大于等于0时,x不等于-1,x可以为1.若x-1>0,则需x+1>0,得到x>1;若x-1
(x-1)/(x+1)≥0且(6-x-x^2)≥0
(x-1)(x+1)≥0且(x+1)≠0且6-x-x^2≥0
x小于-1或x≥1且-3≤x≤2
取并集 定义域是[-3,-1)∪[1,2]