(a^2bc)^4/(ab^2c)^3·(abc)^2 急!
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 17:23:15
x
1D[V}ƍ F:G4@#@Bk>dϞ9IÑ#d7AxKGE9\mDp ),KzUcO]PR36tK_n$u_&
h}B;GJujy
(a^2bc)^4/(ab^2c)^3·(abc)^2 急!
(a^2bc)^4/(ab^2c)^3·(abc)^2 急!
(a^2bc)^4/(ab^2c)^3·(abc)^2 急!
(a^2bc)^4/(ab^2c)^3·(abc)^2
=a^8b^4c^4÷(a^3b^6c^3)*(a^2b^2c^2)
=a^(8-3+2)b^(4-6+2)c^(4-3+2)
=a^7c^3
(a^2bc)^4/[(ab^2c)^3(abc)^2]
=a^8b^4c^4/a^5b^8c^5
=a^3/b^4c