(60-2x)(40-4x)=800

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(60-2x)(40-4x)=800
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(60-2x)(40-4x)=800
(60-2x)(40-4x)=800

(60-2x)(40-4x)=800
由原方程两边同除8得:(30-x)(10-x)=100
展开:x^2-40x+300=100
x^2-40x-200=0
(x-20)^2=200
x-20=正负10根号2
所以x=20+正负10根号2

展开得:2400-240x-80x+8x²=800
移项整理得:8x²-320x+1600=0
化简得:x²-40x+200=0
解得:x=20±10√2

(60-2x)(40-4x)=800
(x-30)(2x-20)=400
2x^2 - 80x +200=0
x^2 - 40x +100=0
(x-20)^2 = 300
x=20 ± 10√3

多项式乘多项式,分别乘开60x40-60x4x-2xx40+2xx4x=800
2400-240x -80x+8x²=800 8x²-320x+1600=0
两边同时除以8得x²-40x+200=0 x=-b ±√b²-2ac/2a=-40±√1600-400/2=-20±10√3

x-(x/2-40)-(x/4+60)=60求解 40-2x=60-4x x等于多少? 40%(4-x)+60%x=2 X+X-6+X-4+X/2=60 (4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60) x-2=(104-x)+2 6x-59=10x-75 (x+10)+(x-15)=280-x4(x-62)=x-38 60x-40=(60+20)*(x-5) 32x+32*0.5-25x+64x=24x+496-49x x+15=3*(109-x ) 5(3x-1.4)=2(6x-0.5) 3(x+0.9)=5(x-1.7) 13x-4(2x+5)=17(x-2)-4(2x-1) (13x+8)/3=5x-1x-60=2[(3561-x)+100]+1 (x+9)+12=2[(x-9)-1 (60-2x)(40-4x)=800 60%x+25=40 x+30%x=52 19-120%x=7 4分之3x-5%x=17.5 x-10%x=18 (1-25%)x=36 2x+30%x=9.2 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解 (40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 x^2-30X+200=0 (X-10)(X-20)=0 X-10=0 X-20=0(X-10)(X-20)=0 40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 ^2-30X+200=0 (X-10)(X-20)=0 (x/x-2)+(2/x*2+2x)-(x+6/x*2-4)化简,=x^2/x(x-2)+(2x-4)/x(x^2-4)-(x^2+6x)/x(x^2-4)=x^2/x(x-2)-(x+2)/x(x-2)=(x-2)(x+1)/x(x-2)=(x+1)/x 先化简,再求值:(x-2/x-x+2/x)/x-2/4x,x=2011 (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x-2x+3x-4x+5x.+99x-100x=25求解 2x+3x+4x+5x+x+6x+7x=100 x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x