(x+3)(x-3)-(x+3)²-(x-1)(x+2)
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(x+3)(x-3)-(x+3)²-(x-1)(x+2)
(x+3)(x-3)-(x+3)²-(x-1)(x+2)
(x+3)(x-3)-(x+3)²-(x-1)(x+2)
(x+3)(x-3)-(x+3)²-(x-1)(x+2)
=x方-9-(x方+6x+9)-(x方+x-2)
=x方-9-x方-6x-9-x方-x+2
=-x方-7x-16
(x+3)(x-3)-(x+3)的平方-(x-1)(x+2)
=(x²-9)-(x²+6x+9)-(x²-x-2)
=x²-9-x²-6x-9-x²+x+2
=x²-5x-16可多项式与多项式相乘,不应该用多项式中的一项与另一个多项式中的每一项相乘,再把所得的积相加吗这有简便算法的 ,也可以像你说...
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(x+3)(x-3)-(x+3)的平方-(x-1)(x+2)
=(x²-9)-(x²+6x+9)-(x²-x-2)
=x²-9-x²-6x-9-x²+x+2
=x²-5x-16
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