求一道数学题那部分错了?并改正.1/(x-4)+4/(x+1)=2/(x-3)+3/(x-2)1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1) ①(-2x+10)/(x²-6+8)=(-2x+10)/(x²-4x+3) ②1/(x²-6x+8)=1/(x²-4x+3) ③x²-6x+8=x²-4x+3 ④x=5/2我怎么都觉得
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 13:46:49
![求一道数学题那部分错了?并改正.1/(x-4)+4/(x+1)=2/(x-3)+3/(x-2)1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1) ①(-2x+10)/(x²-6+8)=(-2x+10)/(x²-4x+3) ②1/(x²-6x+8)=1/(x²-4x+3) ③x²-6x+8=x²-4x+3 ④x=5/2我怎么都觉得](/uploads/image/z/4387621-13-1.jpg?t=%E6%B1%82%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%E9%82%A3%E9%83%A8%E5%88%86%E9%94%99%E4%BA%86%3F%E5%B9%B6%E6%94%B9%E6%AD%A3.1%2F%28x-4%29%2B4%2F%28x%2B1%29%3D2%2F%28x-3%29%2B3%2F%28x-2%291%2F%28x-4%29-3%2F%28x-2%29%3D2%2F%28x-3%29-4%2F%28x-1%29+%E2%91%A0%28-2x%2B10%29%2F%28x%26sup2%3B-6%2B8%29%3D%28-2x%2B10%29%2F%28x%26sup2%3B-4x%2B3%29+%E2%91%A11%2F%28x%26sup2%3B-6x%2B8%29%3D1%2F%28x%26sup2%3B-4x%2B3%29+%E2%91%A2x%26sup2%3B-6x%2B8%3Dx%26sup2%3B-4x%2B3+%E2%91%A3x%3D5%2F2%E6%88%91%E6%80%8E%E4%B9%88%E9%83%BD%E8%A7%89%E5%BE%97)
求一道数学题那部分错了?并改正.1/(x-4)+4/(x+1)=2/(x-3)+3/(x-2)1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1) ①(-2x+10)/(x²-6+8)=(-2x+10)/(x²-4x+3) ②1/(x²-6x+8)=1/(x²-4x+3) ③x²-6x+8=x²-4x+3 ④x=5/2我怎么都觉得
求一道数学题那部分错了?并改正.
1/(x-4)+4/(x+1)=2/(x-3)+3/(x-2)
1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1) ①
(-2x+10)/(x²-6+8)=(-2x+10)/(x²-4x+3) ②
1/(x²-6x+8)=1/(x²-4x+3) ③
x²-6x+8=x²-4x+3 ④
x=5/2
我怎么都觉得是对的 但题目说要错
求一道数学题那部分错了?并改正.1/(x-4)+4/(x+1)=2/(x-3)+3/(x-2)1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1) ①(-2x+10)/(x²-6+8)=(-2x+10)/(x²-4x+3) ②1/(x²-6x+8)=1/(x²-4x+3) ③x²-6x+8=x²-4x+3 ④x=5/2我怎么都觉得
(-2x+10)/(x²-6+8)=(-2x+10)/(x²-4x+3) ②
1/(x²-6x+8)=1/(x²-4x+3) ③
同时除以一个数要先讨论是否等于0,这步漏掉了一个根.
第三部
两边除以(-2x+10),而-2x+10可能为0
第二步中(-2x+10)不能同时除去 因为它不一定非零
②到③,你把(-2x+10) 销掉了,
忽略了(-2x+10) 为0 的情况,少了一个解
也就是x=5的解
②到③错 不可以直接就消掉-2x+10 因为无法判断是否为0