作业帮计算：[(-3x²y∧4)²·x²-2x(3x²y²)³·1/3y²]÷9x∧7y∧8
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/26 18:38:04
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计算：[(-3x²y∧4)²·x²-2x(3x²y²)³·1/3y²]÷9x∧7y∧8
计算：[(-3x²y∧4)²·x²-2x(3x²y²)³·1/3y²]÷9x∧7y∧8
计算：[(-3x²y∧4)²·x²-2x(3x²y²)³·1/3y²]÷9x∧7y∧8
[(-3x²y∧4)²·x²-2x(3x²y²)³·1/3y²]÷9x∧7y∧8
=(-3x^6y^8-18x^7y^4)÷9x^7y^8
=-1/3x^(-1) - 2y^(-4)
=1/3x - 2/y^4
（y∧4-2x)/xy∧4