(1/x-3)-(1/x^2-9)-(1/6+2x)
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(1/x-3)-(1/x^2-9)-(1/6+2x)
(1/x-3)-(1/x^2-9)-(1/6+2x)
(1/x-3)-(1/x^2-9)-(1/6+2x)
应该是1/(x-3)-1/(x^2-9)-1/(6+2x)
1/(x-3)-1/(x^2-9)-1/(6+2x)
=1/(x-3)-1/[(x+3)(x-3)]-1/[2(x+3)]
=2(x+3)/[2(x-3)(x+3)]-2/[2(x+3)(x-3)]-(x-3)/[3(x+3)(x-3)]
=[2(x+3)-2-(x-3)]/[2(x+3)(x-3)]
=[x+7]/[2(x+3)(x-3)]
=(x+7)/[2(x^2-9)]
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