(x-y)²-(x-y)因式分解
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(x-y)²-(x-y)因式分解
(x-y)²-(x-y)因式分解
(x-y)²-(x-y)因式分解
(x-y(x-y-1)
原式=(x+y)(x-y)-(x-y)=(x-y)(x+y-1)
(x-y)²-(x-y)
=(x-y)(x-y-1)
=x²+y²-2xy-x+y;楼主给分啊。。。
由式得(x-y)(x+y-1)