1/1X2+1/2X3+1/3X4···+1/2006X2007（怎么做呀)小弟感激不尽!

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/23 20:41:28
1/1X2+1/2X3+1/3X4···+1/2006X2007（怎么做呀)小弟感激不尽!
xRN@1R"l ѭ~!aY /"Qq!hb: X"FblɝssZ-%YWYRtVUx׉Db:,q. 8[ o7ñpgmlJEyI2tTDp8) E"!+T*TH0n࡯A  <2(C:V{r,Rwvu XsU$FRHypJH6&MW>޲ l Hr]л3&D䨞ؼfnYRSo/l~1VO' jaٵ+Rt MR#2% Ƶo; LSP 3T$28Lj!q/ 잂

1/1X2+1/2X3+1/3X4···+1/2006X2007（怎么做呀)小弟感激不尽!
1/1X2+1/2X3+1/3X4···+1/2006X2007（怎么做呀)
小弟感激不尽!

1/1X2+1/2X3+1/3X4···+1/2006X2007（怎么做呀)小弟感激不尽!
1/1x2+1/2x3+1/3x4+...+1/2007
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+(1/2007)
=1-1/2+1/2-1/3+1/3-1/4+……+1/2007
中间互相抵消
=2006/2007
参考资料：仅供参考,

1/1*2拆成1/1-1/2
1/2*3拆成1/2-1/3
以此类推
原式=（1-1/2）+(1/2-1/3)+(1/3-1/4)+...+(1/2005-1/2006)+(1/2006-1/2007)
中间的都可以相抵消=1-1/2007
=2006/2007

1/1*2拆成1/1-1/2
1/2*3拆成1/2-1/3
可以看见此题的规律，按上面的方法一次类推！
=1-1/2007
=2006/2007

1/n(n+1)=1/n-1/(n+1)
原式=(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+(1/2006-1/2007)
=1-(1/2-1/2)-(1/3-1/3)-……-(1/2006-1/2006)-1/2007
=1-1/2007
=2006/2007

1x2+2x3+3x4+···+10x11 用克拉默法则解下列方程组 x1-2x2+3x3-4x4=4 x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3x1-2x2+3x3-4x4=4x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3 因式分解：x4+x3+2x2 +x+1 解方程组X1-2x2+3x3-x4=1,3x1-x2+5x3-3x4=2,2x1+x2+2x3-2x4=3 x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1 写出方程组2*x1+x2-x3+x4=1,x1+2*x2+x3-x4=2,x1+x2+2*x3+x4=3的通解? 求非齐次线方程组的通解 ：2x1+x2-x3+x4=1 x1+2x2+x3-x4=2 x1+x2+2x3+x4=3 具体写出方程组：2x1+x2-x3+x4=1;x1+2x2+x3-x4=2;x1+x2+2x3+x4=3的通解 解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2 用初等行变换来解下列线性方程组（1）2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2 1X2+2X3+3X4+.NX(N+1) 1X2+2X3+3X4+.NX(N+1)规律 1x2+2x3+3x4+.+2011x2012 1x2+2x3+3x4+4x5+.+15x16 1x2+2x3+3x4+.+100x101= 1x2+2x3+3x4+.+100x101=?结果 1x1!+2x2!+3x3!+4x4!.nxn! 1X2+2x3+3x4+……+2013x2014