(m-n)(m+n)+(m+n)²-2m²
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(m-n)(m+n)+(m+n)²-2m²
(m-n)(m+n)+(m+n)²-2m²
(m-n)(m+n)+(m+n)²-2m²
解=m^2-n^2+(m+n-2m)(m+n+2m)
=m^2-n^2+(n-m)(3m+n)
=m^2-n^2+2mn+n^2-3m^2
=2mn-2m^2
=2m(n-m)