5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 07:52:27
5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,
x)3MTS64֎14`BPL,Q3Vi';&ھ2ɮmOvv?ѠcTO] lm:arF0Ef0DM4BahhiiiyFF~qAb(62

5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,
5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,

5a²+[a²+(5a²-3a²)-6(a²-a)],其中a=负二分之一,
5a²+[a²+(5a²-3a²)-6(a²-a)],
=5a²+(a²+2a²-6a²+6a)
=5a²+a²+2a²-6a²+6a
=2a²+6a
=2*1/4+6*(-1/4)
=1/2-3/2
=-1