解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)答案是x1=-1/3,x2=7

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/23 18:58:48
解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)答案是x1=-1/3,x2=7
xRJ0&m-JO=IăYś(*xPЅe?Flw=/84i+`/yސ*wx2?bIKb]$D'#dzJ5O Pr/"_UeOֳQ֧o7٤VGz<˩Jdj-pG-ߡՋEܨL)ujglxY/mIims La k ])߁ay3g#mj Fr 8z*Zgen ,,,ajS.E폼>sa!š4L

解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)答案是x1=-1/3,x2=7
解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)
答案是x1=-1/3,x2=7

解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)答案是x1=-1/3,x2=7
13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)
左右两边分别通分得
(3x+1)/(x-4)(x-3)=(3x+1)/(x-5)(x-1)
∴3x+1=0或(x-4)(x-3)=(x-5)(x-1)
∴x=-1/3或x=7

13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)
(13x-39-10x+40)/(x^2-7x+12)=(4x-4-x+5)/(x^2-6x+5)
(3x+1)(x^2-6x+5)=(3x+1)(x^2-7x+12)
3x+1=0
x=-1/3

x^2-6x+5=x^2-7x+12
7x-6x=12-5
x=7

(13x-39-10x+40)/(x-4)(x-3)=(4x-4-x+5)/(x-5)(x-1)
(3x+1)(x-5)(x-1)=(3x+1)(x-4)(x-3)
3x+1=0 or (x-5)(x-1)=(x-4)(x-3)
1,
x1=-1/3
2,x^2-6x+5=x^2-7x+12
x2=7