(x-y)(2x-y-1)

来源：学生作业帮助网编辑：作业帮时间：2024/11/15 06:23:00

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(x-y)(2x-y-1)
(x-y)(2x-y-1)

(x-y)(2x-y-1)
(1+5)×(10-6)=24
(10-1-5)×6=24
(a+b)2=22
a2+b2+2ab=4
a2+b2=4-2ab=4+2=6
所以b/a+a/b
=(a2+b2)/ab
=6/(-1)
=-6

1/(2x) - 1/(x+y)*((x+y)/(2x)-x-y)
=1/(2x) - 1/(x+y)*(x+y)(1/2x-1)
=1/(2x) - (1/2x-1)
=1

1+2得到2x+z=27.........4
1+3得到3x+2z=44...........5
4*2得到4x+2z=54............6
6-5得到x=10
把x=10代入5得到2z=44-30
z=7
把x=10代入2得到10-y=1
y=9
所以原方程组的解为x=10,y=9,z=7

2x^2-3xy+y^2-x+y

[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z) x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 (x-y)(2x-y-1) (x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简 x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² 化简y(x+y)+(x+y)(x-y)-x^2 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 (x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) [(-2x-y)^2-(2x+y)(2x-y)]÷2y-1/2y 因式分解x(x+y)(x-y)-x(x+y)^2 (x-y/1-x+y/1)÷2y/y-x计算错了，是(1/x-y-1/x+y)÷2y/y-x 求(1+y)-2x(1+y)+x(1-y) 把4（x-y+1)+y(y-2x)因式分解