已知x²+y²+4x+6y+13=0,求(x+y)²的值
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已知x²+y²+4x+6y+13=0,求(x+y)²的值
已知x²+y²+4x+6y+13=0,求(x+y)²的值
已知x²+y²+4x+6y+13=0,求(x+y)²的值
x²+y²+4x+6y+13=0
所以
(x+2)²+(y+3)²=0
所以
x+2=0,y+3=0
x=-2,y=-3
x+y=-2-3=-5