∫[cos2x/(cos²xsin²x)]dx等于多少?
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∫[cos2x/(cos²xsin²x)]dx等于多少?
∫[cos2x/(cos²xsin²x)]dx等于多少?
∫[cos2x/(cos²xsin²x)]dx等于多少?
原式=∫4cos2x/sin²2x dx
=2∫cos2x/sin²2x d(2x)
=2∫dsin2x/sin²2x
=-2/sin2x+C