√x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y

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√x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y
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√x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y
√x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y

√x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y
√x(√x+2√y)=√y(6√x+5√y)
(√x)²-4√(xy)-5(√y)²=0
(√x-5√y)(√x+√y)=0
∴√x=5√y √x=-√y 舍去
原式=[(√x)²-3√x√y+2y]/[(√x)²+√x√y-6y]
=(25y-15y+2y)/(25y+5y-6y)
=12y/24y
=1/2