(xy^2-x)dx-(y+yx^2)dy=0,求这个微分方程的通解.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 00:27:07
x)Ө3ҭLըԮ3L5yOvzoӎgv>_|VˆY//ֳI*'[~
e6WjjC5Th1IԇVTk ijrj25F@6XvFAuAe¶Fچ!Cu@k$ف<
(xy^2-x)dx-(y+yx^2)dy=0,求这个微分方程的通解.
(xy^2-x)dx-(y+yx^2)dy=0,求这个微分方程的通解.
(xy^2-x)dx-(y+yx^2)dy=0,求这个微分方程的通解.
y(1+x^2)dy=x(y^2-1)dx
ydy/(y^2-1)=xdx/(x^2+1)
ln|y^2-1|/2=ln|x^2+1|/2+C
ln|y^2-1|=ln(x^2+1)+C
y^2-1=C(x^2+1)
y^2=C(x^2+1)+1
y=±√(C(x^2+1)+1)
求方程(y^2+xy^2)dx+(x^2-yx^2)dy=0的通解
(xy^2-x)dx-(y+yx^2)dy=0,求这个微分方程的通解.
解微分方程y(x^2-xy+y^2)+x(x^2+xy+y^2)dy/dx=0答案yx=ce^[-arctan(y/x)]
L为x^2+y^2=4,计算∮(x-yx^2)dx+(xy^2)dy的值?
(x³-2xy²)dy+(2y³-3yx²)dx=0求通解
-x^2y+5xy^2-yx^2合并同类项
xy^2-x-yx^2+y变为(y-x)(xy+1)xy^2-x-yx^2+y化为(y-x)(xy+1)感觉不像十字相乘法.
∫C (yx^3+e^y)dx+(xy^3+xe^y-2y)dy,其中C为正向圆周x^2+y^2=a^2
求方程dy/dx=(1+y^2)/(xy+yx^3)的解.
一道常微分中变量可分离方程dy/dx=(1+y^2)/(xy+yx^3),
求 ∫L(-yx^2-2y)dx+(xy^2+x)dy L是逆时针方向的园x^2+y^2=a^2
求微分方程(y^2+xy^2)dx-(x^2+yx^2)dy=0,满足初始条件(y/x=1)=-1的特解
求dy/dx=x+xy^/y+yx^满足初始条件y|(下面是x=0) =2的特解.^是2,2次方
求dy/dx=x+xy^/y+yx^满足初始条件y|(下面是x=0)=2的特解.
3xy+xy+2x²y+yx²+3x²y等于多少
xy-3xy+2yx-yx
(xy-x^2)÷x^2-2xy+y^2/xy*x-y/y^2*yx^-2(xy-x^2)÷{x^2-2xy+y^2/xy}*{x-y/y^2}*{yx^-2}
因式分解x^2+xy+3x+3yx^2+xy+3x+3y 因式分解