若(x-z)^2-4(x-y)(y-z)=0,求x+z与y的关系
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若(x-z)^2-4(x-y)(y-z)=0,求x+z与y的关系
若(x-z)^2-4(x-y)(y-z)=0,求x+z与y的关系
若(x-z)^2-4(x-y)(y-z)=0,求x+z与y的关系
(x-z)^2-4(x-y)(y-z)=0
X*2-2XZ+Z*2-4XY-4YZ+4XZ+4Y*2=0
X*2+2XZ+Z*2-4Y(X+Z)+4Y*2=0
(X+Z)*2-4Y(X+Z)+4Y*2=0
{(X+Z)-2Y}*2=0
(X+Z)-2Y=0
X+Z=2Y
若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)=
若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-x)=
(x-y)^2+4z(x-y)+4z^2
化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z}
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x+y/2=z+x/3=y+z/4 x+y+z=27
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