实数x,y满足|x+y|≤1,|x-y|≤1.证明|x|+|y|≤1.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 02:01:24
x){n*t*^b
ʚGKuj*t!,諩Ѯ$铩SΆ[Jl48#"HۨR"U^M.za@/.H̳y ֩
实数x,y满足|x+y|≤1,|x-y|≤1.证明|x|+|y|≤1.
实数x,y满足|x+y|≤1,|x-y|≤1.证明|x|+|y|≤1.
实数x,y满足|x+y|≤1,|x-y|≤1.证明|x|+|y|≤1.
|x+y|≤1 => (x+y)^2≤1 => x^2+2xy+y^2≤1
|x-y|≤1 => (x-y)^2≤1 => x^2-2xy+y^2≤1
x^2+y^2≤1
|x|+|y|≤x^2+y^2≤1