在△ABC中,∠BAC=90°,AB=AC,F为AB上一点,延长CA到E,使AE=AF,CF的延长交BF于D.求证:CD⊥BE
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![在△ABC中,∠BAC=90°,AB=AC,F为AB上一点,延长CA到E,使AE=AF,CF的延长交BF于D.求证:CD⊥BE](/uploads/image/z/4534591-31-1.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D90%C2%B0%2CAB%3DAC%2CF%E4%B8%BAAB%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E5%BB%B6%E9%95%BFCA%E5%88%B0E%2C%E4%BD%BFAE%3DAF%2CCF%E7%9A%84%E5%BB%B6%E9%95%BF%E4%BA%A4BF%E4%BA%8ED.%E6%B1%82%E8%AF%81%EF%BC%9ACD%E2%8A%A5BE)
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