直三棱柱ABC-A1B1C1中,AB=1,AC=AA1=根号3,角ABC=60° 证明:1、AB垂直A1C 2、求二面角A-A1C-B的大小
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![直三棱柱ABC-A1B1C1中,AB=1,AC=AA1=根号3,角ABC=60° 证明:1、AB垂直A1C 2、求二面角A-A1C-B的大小](/uploads/image/z/4542364-28-4.jpg?t=%E7%9B%B4%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%E4%B8%AD%2CAB%3D1%2CAC%3DAA1%3D%E6%A0%B9%E5%8F%B73%2C%E8%A7%92ABC%3D60%C2%B0+%E8%AF%81%E6%98%8E%EF%BC%9A1%E3%80%81AB%E5%9E%82%E7%9B%B4A1C+2%E3%80%81%E6%B1%82%E4%BA%8C%E9%9D%A2%E8%A7%92A-A1C-B%E7%9A%84%E5%A4%A7%E5%B0%8F)
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