(1/2000-1)*(1/1999-1)*…*(1/1001-1)*(1/1000-1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 15:49:19
![(1/2000-1)*(1/1999-1)*…*(1/1001-1)*(1/1000-1)](/uploads/image/z/468386-26-6.jpg?t=%EF%BC%881%2F2000-1%EF%BC%89%2A%EF%BC%881%2F1999-1%EF%BC%89%2A%E2%80%A6%2A%281%2F1001-1%29%2A%281%2F1000-1%29)
x){P@N-0}LK(```k ej$铭WΆ2Vlm6@_l]Z.L~qAbE S
(1/2000-1)*(1/1999-1)*…*(1/1001-1)*(1/1000-1)
(1/2000-1)*(1/1999-1)*…*(1/1001-1)*(1/1000-1)
(1/2000-1)*(1/1999-1)*…*(1/1001-1)*(1/1000-1)
原式=-1999/2000*(-1998/1999)*……*(-1000/1001)*(-999/1000)=-999/2000
1999÷1999/1999/2000+1/2001
2000*(1-1/2)*(1-1/3)*.*(1-1/1999)*(1-1/2000)
2000*(1-1/2*)*(1-1/3)*...*(1-1999)*(1-1/2000)
(1/2000-1)*(1/1999-1)*…*(1/1001-1)*(1/1000-1)
1999÷(1999+1999/2000)+1/2000怎么算啊
2000-1999+1998.+2-1
(1+1/1998+1/1999)*(1/1998+1/1999+1/2000)-(1+1/1998+1/1999+1/2000
计算|1/2001|-1/2000+|1/2000-1/1999|-|1/1999-1/2001|
1999除以1999又1999/2000加1/2001 简算
1999÷1999又1999/2000+1/2001
用简便计算法:(1)1999×1999+2000+1999;
1999/1999又1999/2000+1/2001要简便算法
1/(1996*1997)+1/(1997*1998)+1/(1998*1999)+1/(1999*2000)+1/2000
(1-1/2²)(1-1/3²)...(1-1/1999²)(1-1/2000²)
(2+5+8+...+2000)-(1+4+7+...+1999)
(1+1/1999+1/2000)*(1/1999+1/2000+1/2001+1/2002)-(1+1/1999+1/2000+1/2001+1/2002)*(1/1999+1/2000+1/2001) 用简便方法计算1/2001)
1^1999+2^1999+~~~+2000^1999能被1+2+~~~+2000整除
根号(1999*2000*2001*2002+1)化简