因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y急 十万火急 13:40之前有奖励!

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/02 16:26:48
因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y急 十万火急 13:40之前有奖励!
x){:{=O;^,_~Ϭ{:*Ԕ -+!nE= ]0mi =YROv?o\ [<ٜΧK=ڨhTOUkb ;9^qA*u A !aSLRSF 16`kխFU #4C`j7L0qD~z7t?]4LP( m6vT0uXFU4)8z$IXToE YƐ

因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y急 十万火急 13:40之前有奖励!
因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
急 十万火急
13:40之前有奖励!

因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y急 十万火急 13:40之前有奖励!
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
=[x²y(xy-1)-x²y(1-xy)]÷3x²y
=x²y[(xy-1)-(1-xy)]÷3x²y
=x²y[2(xy-1)]÷3x²y
=2(xy-1)/3

[x(x²y²-xy)-y(x²-x³y)]÷3x²y
=[x³y²-x²y-yx²+x³y²]÷3x²y
=[2x³y²-2x²y]÷3x²y
=【2xy-2】/3

原式=[x²y(xy-1)-x²y(1-xy)]÷3x²y
=(xy-1-1+xy)÷3
=(2xy+2)/3

:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
=(x³y²-x²y-x²y+x³y²)÷3x²y
=(2x³y²-2x²y)÷3x²y
=2x²y(xy-1)÷3x²y
=2/3(xy-1)