假定有“struct BOOK{char title[40]; float price;}book;”,则正确的语句为( ).a、BOOK&x=&bookb、BOOK&x=bookc、BOOK&x=newBOOKd、BOOK&x=BOOK
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![假定有“struct BOOK{char title[40]; float price;}book;”,则正确的语句为( ).a、BOOK&x=&bookb、BOOK&x=bookc、BOOK&x=newBOOKd、BOOK&x=BOOK](/uploads/image/z/4694884-52-4.jpg?t=%E5%81%87%E5%AE%9A%E6%9C%89%E2%80%9Cstruct+BOOK%7Bchar+title%5B40%5D%3B+float+price%3B%7Dbook%3B%E2%80%9D%2C%E5%88%99%E6%AD%A3%E7%A1%AE%E7%9A%84%E8%AF%AD%E5%8F%A5%E4%B8%BA%EF%BC%88+%EF%BC%89.a%E3%80%81BOOK%26x%3D%26bookb%E3%80%81BOOK%26x%3Dbookc%E3%80%81BOOK%26x%3DnewBOOKd%E3%80%81BOOK%26x%3DBOOK)
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假定有“struct BOOK{char title[40]; float price;}book;”,则正确的语句为( ).a、BOOK&x=&bookb、BOOK&x=bookc、BOOK&x=newBOOKd、BOOK&x=BOOK
假定有“struct BOOK{char title[40]; float price;}book;”,则正确的语句为( ).
a、BOOK&x=&book
b、BOOK&x=book
c、BOOK&x=newBOOK
d、BOOK&x=BOOK
假定有“struct BOOK{char title[40]; float price;}book;”,则正确的语句为( ).a、BOOK&x=&bookb、BOOK&x=bookc、BOOK&x=newBOOKd、BOOK&x=BOOK
答案是 b 吧
代码是 c++ 的 么,&x 是 定义了一个 book 的引用 ,不是指针 ,所以是 b