因式分解:(x²+4x-1 )(x ²+4x+5)+9=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/28 13:05:50
![因式分解:(x²+4x-1 )(x ²+4x+5)+9=?](/uploads/image/z/469812-12-2.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%EF%BC%9A%EF%BC%88x%26%23178%3B%EF%BC%8B4x%EF%BC%8D1+%EF%BC%89%EF%BC%88x+%26%23178%3B%EF%BC%8B4x%EF%BC%8B5%EF%BC%89%EF%BC%8B9%EF%BC%9D%3F)
x_J@*%4?դ>-m&6J+|LZ[Co3o>f¼xX보N'Ii_S;-L,T#M o[YQ#SWUpx `$͓li <&iOf!i&> EF!(nL`рBB@c_Ĺ!1#yyBYo\V8*N)Zю."7e]M\|-Y.byhEhn%.]>h[
因式分解:(x²+4x-1 )(x ²+4x+5)+9=?
因式分解:(x²+4x-1 )(x ²+4x+5)+9=?
因式分解:(x²+4x-1 )(x ²+4x+5)+9=?
=[(x+2)^2-5][(x+2)^2+1]+9
=(x+2)^4-4(x+2)^2-5+9
=(x+2)^4-4(x+2)^2+4
=[(x+2)^2-2]^2
=(x^2+4x+2)^2
(x^2+4x+2)^2