【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
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【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
【(x+1/2x-2)-(6/x²-1)-(x+3/2x+2)】·(4x²-4/3)
=【(x+1)/2(x-1)-6/(x+1)(x-1)-(x+3)/2(x+1)】·4(x+1)(x-1)/3
=2/3(x+1)²-8-2/3(x+3)(x-1)
=2/3x²+4/3x+2/3-8-2/3x²-4/3x+2
=2/3-8+2
=-16/3
如果本题有什么不明白可以追问,
你好;原式=[(x2+2x+1)/2(x+1)(x-1)-12/2((x+1)(x-1)-(x2+2x-3)/2((x+1)(x-1)]×4﹙x+1﹚﹙x-1﹚/3﹙先通分) =﹙x2+2x+1-12-x2-...
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你好;原式=[(x2+2x+1)/2(x+1)(x-1)-12/2((x+1)(x-1)-(x2+2x-3)/2((x+1)(x-1)]×4﹙x+1﹚﹙x-1﹚/3﹙先通分) =﹙x2+2x+1-12-x2-2x+3﹚/2((x+1)(x-1)×4﹙x+1﹚﹙x-1﹚/3 =-8/2((x+1)(x-1)×4﹙x+1﹚﹙x-1﹚/3 =-16/3
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