初二数学几何题目如图,在等腰三角形ABC中,角B=90°,D是AC中点,过D做DE⊥DF交B于E,交BC于F,AE=4,CF=3,求EF
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![初二数学几何题目如图,在等腰三角形ABC中,角B=90°,D是AC中点,过D做DE⊥DF交B于E,交BC于F,AE=4,CF=3,求EF](/uploads/image/z/473507-35-7.jpg?t=%E5%88%9D%E4%BA%8C%E6%95%B0%E5%AD%A6%E5%87%A0%E4%BD%95%E9%A2%98%E7%9B%AE%E5%A6%82%E5%9B%BE%EF%BC%8C%E5%9C%A8%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%EF%BC%8C%E8%A7%92B%3D90%C2%B0%EF%BC%8CD%E6%98%AFAC%E4%B8%AD%E7%82%B9%EF%BC%8C%E8%BF%87D%E5%81%9ADE%E2%8A%A5DF%E4%BA%A4B%E4%BA%8EE%EF%BC%8C%E4%BA%A4BC%E4%BA%8EF%EF%BC%8CAE%3D4%EF%BC%8CCF%3D3%EF%BC%8C%E6%B1%82EF)
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