几道纠结的九年级数学三角形比例问题1 已知平行四边形ABCD中、E为AD中点,AF:BF=2:3 求AG:GC的值2 如图,点D是△ABC的边AC中点,过D的直线交AB于点E,交BC的延长线与F求 AE:EB=CF:BF 下面是图谢谢
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![几道纠结的九年级数学三角形比例问题1 已知平行四边形ABCD中、E为AD中点,AF:BF=2:3 求AG:GC的值2 如图,点D是△ABC的边AC中点,过D的直线交AB于点E,交BC的延长线与F求 AE:EB=CF:BF 下面是图谢谢](/uploads/image/z/4818182-14-2.jpg?t=%E5%87%A0%E9%81%93%E7%BA%A0%E7%BB%93%E7%9A%84%E4%B9%9D%E5%B9%B4%E7%BA%A7%E6%95%B0%E5%AD%A6%E4%B8%89%E8%A7%92%E5%BD%A2%E6%AF%94%E4%BE%8B%E9%97%AE%E9%A2%981+%E5%B7%B2%E7%9F%A5%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%E3%80%81E%E4%B8%BAAD%E4%B8%AD%E7%82%B9%2CAF%3ABF%3D2%3A3+%E6%B1%82AG%3AGC%E7%9A%84%E5%80%BC2+%E5%A6%82%E5%9B%BE%2C%E7%82%B9D%E6%98%AF%E2%96%B3ABC%E7%9A%84%E8%BE%B9AC%E4%B8%AD%E7%82%B9%2C%E8%BF%87D%E7%9A%84%E7%9B%B4%E7%BA%BF%E4%BA%A4AB%E4%BA%8E%E7%82%B9E%2C%E4%BA%A4BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8EF%E6%B1%82+AE%3AEB%3DCF%3ABF+++++%E4%B8%8B%E9%9D%A2%E6%98%AF%E5%9B%BE%E8%B0%A2%E8%B0%A2)
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