已知函数f(x)=x^3+mx^2+nx-2的图像过点(-1,-6),且函数g(x)=f'(x)+6x的图像关于y轴对称.求m,n的值.我做出来是m=3,n=6 f ' (x)=3x^2+2mx+n,g(x)为偶函数,所以满足g(x)=g(-x),g(x)=3x^2+2mx+n+6x,所以就有3x^2+(2m+6)x+n=3x^2-(2m
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![已知函数f(x)=x^3+mx^2+nx-2的图像过点(-1,-6),且函数g(x)=f'(x)+6x的图像关于y轴对称.求m,n的值.我做出来是m=3,n=6 f ' (x)=3x^2+2mx+n,g(x)为偶函数,所以满足g(x)=g(-x),g(x)=3x^2+2mx+n+6x,所以就有3x^2+(2m+6)x+n=3x^2-(2m](/uploads/image/z/4957749-45-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dx%5E3%2Bmx%5E2%2Bnx-2%E7%9A%84%E5%9B%BE%E5%83%8F%E8%BF%87%E7%82%B9%28-1%2C-6%29%2C%E4%B8%94%E5%87%BD%E6%95%B0g%28x%29%3Df%27%28x%29%2B6x%E7%9A%84%E5%9B%BE%E5%83%8F%E5%85%B3%E4%BA%8Ey%E8%BD%B4%E5%AF%B9%E7%A7%B0.%E6%B1%82m%2Cn%E7%9A%84%E5%80%BC.%E6%88%91%E5%81%9A%E5%87%BA%E6%9D%A5%E6%98%AFm%3D3%2Cn%3D6+f+%27+%28x%29%3D3x%5E2%2B2mx%2Bn%2Cg%28x%29%E4%B8%BA%E5%81%B6%E5%87%BD%E6%95%B0%2C%E6%89%80%E4%BB%A5%E6%BB%A1%E8%B6%B3g%28x%29%3Dg%28-x%29%2Cg%28x%29%3D3x%5E2%2B2mx%2Bn%2B6x%2C%E6%89%80%E4%BB%A5%E5%B0%B1%E6%9C%893x%5E2%2B%282m%2B6%29x%2Bn%3D3x%5E2-%282m)
已知函数f(x)=x^3+mx^2+nx-2的图像过点(-1,-6),且函数g(x)=f'(x)+6x的图像关于y轴对称.求m,n的值.我做出来是m=3,n=6 f ' (x)=3x^2+2mx+n,g(x)为偶函数,所以满足g(x)=g(-x),g(x)=3x^2+2mx+n+6x,所以就有3x^2+(2m+6)x+n=3x^2-(2m
已知函数f(x)=x^3+mx^2+nx-2的图像过点(-1,-6),且函数g(x)=f'(x)+6x的图像关于y轴对称.求m,n的值.
我做出来是m=3,n=6 f ' (x)=3x^2+2mx+n,g(x)为偶函数,所以满足g(x)=g(-x),g(x)=3x^2+2mx+n+6x,所以就有3x^2+(2m+6)x+n=3x^2-(2m+6)x+n,求出m=3,又f(-1)=(-1)^3+m(-1)^2-n-2=-1+m-n-2= m-n-3=-6,已知m=3,所以求出n=6,是不是这样啊?在网上搜同样的题,答案是m=3,n=0,我怎么算都是这样,我容易粗心,所以想让网友们指出我的错误,
已知函数f(x)=x^3+mx^2+nx-2的图像过点(-1,-6),且函数g(x)=f'(x)+6x的图像关于y轴对称.求m,n的值.我做出来是m=3,n=6 f ' (x)=3x^2+2mx+n,g(x)为偶函数,所以满足g(x)=g(-x),g(x)=3x^2+2mx+n+6x,所以就有3x^2+(2m+6)x+n=3x^2-(2m
由题意得-1+m-n-2=-6化简得m-n=-3求导得f‘(x)=3x*2+2mx+n所以g(x)=3x*2+(2m+6)x+n因为g(x)=g(-x)所以2m+6=0所以m=-3代入m-n=-3得n=0
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