如图,在直角梯形ABCD中,AD//BC,∠ADC=90°,AB=5,AD=8,CD=3,线段AD上有一动点E,过点E作EF⊥AB,垂足为点F.(1)若AF=2,求DE的长;(2)当△AEF与△CED相似时,求DE的长
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![如图,在直角梯形ABCD中,AD//BC,∠ADC=90°,AB=5,AD=8,CD=3,线段AD上有一动点E,过点E作EF⊥AB,垂足为点F.(1)若AF=2,求DE的长;(2)当△AEF与△CED相似时,求DE的长](/uploads/image/z/4966982-62-2.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%9B%B4%E8%A7%92%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%2F%2FBC%2C%E2%88%A0ADC%3D90%C2%B0%2CAB%3D5%2CAD%3D8%2CCD%3D3%2C%E7%BA%BF%E6%AE%B5AD%E4%B8%8A%E6%9C%89%E4%B8%80%E5%8A%A8%E7%82%B9E%2C%E8%BF%87%E7%82%B9E%E4%BD%9CEF%E2%8A%A5AB%2C%E5%9E%82%E8%B6%B3%E4%B8%BA%E7%82%B9F.%EF%BC%881%EF%BC%89%E8%8B%A5AF%3D2%2C%E6%B1%82DE%E7%9A%84%E9%95%BF%EF%BC%9B%EF%BC%882%EF%BC%89%E5%BD%93%E2%96%B3AEF%E4%B8%8E%E2%96%B3CED%E7%9B%B8%E4%BC%BC%E6%97%B6%2C%E6%B1%82DE%E7%9A%84%E9%95%BF)
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