①函数y=(2/3)^(x²-4x-6)的单调递减区间是______(答案:[2,+无穷)或者(2,+无穷))②奇函数f(x)的定义域为R,函数g(x)=x^2+f(x-1)+f(x+1),若g(1)=4,则g(-1)的值为_____(答案:-2)③函数y=(a^2-1)^x在R上递增,
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/20 08:30:13
![①函数y=(2/3)^(x²-4x-6)的单调递减区间是______(答案:[2,+无穷)或者(2,+无穷))②奇函数f(x)的定义域为R,函数g(x)=x^2+f(x-1)+f(x+1),若g(1)=4,则g(-1)的值为_____(答案:-2)③函数y=(a^2-1)^x在R上递增,](/uploads/image/z/5089495-31-5.jpg?t=%E2%91%A0%E5%87%BD%E6%95%B0y%3D%282%2F3%29%5E%28x%26%23178%3B-4x-6%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%E5%8C%BA%E9%97%B4%E6%98%AF______%EF%BC%88%E7%AD%94%E6%A1%88%EF%BC%9A%5B2%2C%2B%E6%97%A0%E7%A9%B7%29%E6%88%96%E8%80%85%282%2C%2B%E6%97%A0%E7%A9%B7%29%EF%BC%89%E2%91%A1%E5%A5%87%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BAR%2C%E5%87%BD%E6%95%B0g%28x%29%3Dx%5E2%2Bf%28x-1%29%2Bf%28x%2B1%29%2C%E8%8B%A5g%281%29%3D4%2C%E5%88%99g%28-1%29%E7%9A%84%E5%80%BC%E4%B8%BA_____%EF%BC%88%E7%AD%94%E6%A1%88%EF%BC%9A-2%EF%BC%89%E2%91%A2%E5%87%BD%E6%95%B0y%3D%28a%5E2-1%29%5Ex%E5%9C%A8R%E4%B8%8A%E9%80%92%E5%A2%9E%2C)
xUNA~&
]`6HC/U[ެH
RE*HP* ;r+rf3ltb}ڥO& P*#C#Q;̶fmF`Gsslq^tuc쨗v&>)*vwc0RPt/8)88uvx
Ez\ɀ
P:$mk)ڙ7 CJ{;(},TOhs