如图,正方形ABCD中,P,Q分别在BC,CD上,∠PAQ=45°.若AQ交BC的延长线于E,AB=4,BP=1,求PE,[3]若AP交BD于F点,连FQ,求证AF=FQ.就差一三问.明天就要上交了.
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![如图,正方形ABCD中,P,Q分别在BC,CD上,∠PAQ=45°.若AQ交BC的延长线于E,AB=4,BP=1,求PE,[3]若AP交BD于F点,连FQ,求证AF=FQ.就差一三问.明天就要上交了.](/uploads/image/z/5103272-56-2.jpg?t=%E5%A6%82%E5%9B%BE%2C%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CP%2CQ%E5%88%86%E5%88%AB%E5%9C%A8BC%2CCD%E4%B8%8A%2C%E2%88%A0PAQ%3D45%C2%B0.%E8%8B%A5AQ%E4%BA%A4BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EE%2CAB%3D4%2CBP%3D1%2C%E6%B1%82PE%2C%5B3%5D%E8%8B%A5AP%E4%BA%A4BD%E4%BA%8EF%E7%82%B9%2C%E8%BF%9EFQ%2C%E6%B1%82%E8%AF%81AF%EF%BC%9DFQ.%E5%B0%B1%E5%B7%AE%E4%B8%80%E4%B8%89%E9%97%AE.%E6%98%8E%E5%A4%A9%E5%B0%B1%E8%A6%81%E4%B8%8A%E4%BA%A4%E4%BA%86.)
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