Eviews结果如下怎么判断有没有单位根啊?有两个P值小于0.05,而有两个大于0.05,拒绝还是接受原假设?Pool unit root test:Summary \x05Series:YBJ,YTJ,YHEBEI,YSHX,YNMG,YLN,YJL,YHLJ,YSHH,YJS,YZHJ,YAH,YFJ,YJX,YSHD,YHENAN,YHUBEI,Y
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![Eviews结果如下怎么判断有没有单位根啊?有两个P值小于0.05,而有两个大于0.05,拒绝还是接受原假设?Pool unit root test:Summary \x05Series:YBJ,YTJ,YHEBEI,YSHX,YNMG,YLN,YJL,YHLJ,YSHH,YJS,YZHJ,YAH,YFJ,YJX,YSHD,YHENAN,YHUBEI,Y](/uploads/image/z/5107186-10-6.jpg?t=Eviews%E7%BB%93%E6%9E%9C%E5%A6%82%E4%B8%8B%E6%80%8E%E4%B9%88%E5%88%A4%E6%96%AD%E6%9C%89%E6%B2%A1%E6%9C%89%E5%8D%95%E4%BD%8D%E6%A0%B9%E5%95%8A%3F%E6%9C%89%E4%B8%A4%E4%B8%AAP%E5%80%BC%E5%B0%8F%E4%BA%8E0.05%2C%E8%80%8C%E6%9C%89%E4%B8%A4%E4%B8%AA%E5%A4%A7%E4%BA%8E0.05%2C%E6%8B%92%E7%BB%9D%E8%BF%98%E6%98%AF%E6%8E%A5%E5%8F%97%E5%8E%9F%E5%81%87%E8%AE%BE%3FPool+unit+root+test%3ASummary+%5Cx05Series%3AYBJ%2CYTJ%2CYHEBEI%2CYSHX%2CYNMG%2CYLN%2CYJL%2CYHLJ%2CYSHH%2CYJS%2CYZHJ%2CYAH%2CYFJ%2CYJX%2CYSHD%2CYHENAN%2CYHUBEI%2CY)
Eviews结果如下怎么判断有没有单位根啊?有两个P值小于0.05,而有两个大于0.05,拒绝还是接受原假设?Pool unit root test:Summary \x05Series:YBJ,YTJ,YHEBEI,YSHX,YNMG,YLN,YJL,YHLJ,YSHH,YJS,YZHJ,YAH,YFJ,YJX,YSHD,YHENAN,YHUBEI,Y
Eviews结果如下怎么判断有没有单位根啊?有两个P值小于0.05,而有两个大于0.05,拒绝还是接受原假设?
Pool unit root test:Summary \x05
Series:YBJ,YTJ,YHEBEI,YSHX,YNMG,YLN,YJL,YHLJ,YSHH,YJS,YZHJ,
YAH,YFJ,YJX,YSHD,YHENAN,YHUBEI,YHUNAN,YGD,YGX,
YHAINAN,YCHQ,YSCH,YGZH,YYN,YSHXI,YGS,YQH,YNX,YXJ
Date:02/25/12 Time:09:44\x05
Sample:1997 2009\x05\x05
Exogenous variables:Individual effects
Automatic selection of maximum lags\x05
Automatic lag length selection based on SIC:0 to 1
and Bartlett kernel\x05\x05
\x05\x05\x05\x05
\x05\x05\x05\x05
\x05\x05\x05Cross-\x05
Method\x05Statistic\x05Prob.**\x05sections\x05Obs
Null:Unit root (assumes common unit root process)
Levin,Lin & Chu t*\x05-6.78531\x05 0.0000\x05 30\x05 356
\x05\x05\x05\x05
Null:Unit root (assumes individual unit root process)
Im,Pesaran and Shin W-stat \x05-1.36644\x05 0.0859\x05 30\x05 356
ADF - Fisher Chi-square\x05 70.7329\x05 0.1619\x05 30\x05 356
PP - Fisher Chi-square\x05 91.2017\x05 0.0058\x05 30\x05 360
\x05\x05\x05\x05
\x05\x05\x05\x05
** Probabilities for Fisher tests are computed using an asymptotic Chi
-square distribution.All other tests assume asymptotic normality.
Eviews结果如下怎么判断有没有单位根啊?有两个P值小于0.05,而有两个大于0.05,拒绝还是接受原假设?Pool unit root test:Summary \x05Series:YBJ,YTJ,YHEBEI,YSHX,YNMG,YLN,YJL,YHLJ,YSHH,YJS,YZHJ,YAH,YFJ,YJX,YSHD,YHENAN,YHUBEI,Y
p值过大,则不能拒绝原假设(与你选的显著水平有关),原假设是序列为单位根过程(非平稳).