设函数f(x)=3sin(ωx+π/6),ω>0,x∈(-∞,+∞)且以π/2为最小正周期(1)求f(0)(2)求f(x)的解析式(3)已知f(α/4+π/12)=9/5求sinα的值
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设函数f(x)=3sin(ωx+π/6),ω>0,x∈(-∞,+∞)且以π/2为最小正周期(1)求f(0)(2)求f(x)的解析式(3)已知f(α/4+π/12)=9/5求sinα的值
设函数f(x)=3sin(ωx+π/6),ω>0,x∈(-∞,+∞)且以π/2为最小正周期(1)求f(0)
(2)求f(x)的解析式(3)已知f(α/4+π/12)=9/5求sinα的值
设函数f(x)=3sin(ωx+π/6),ω>0,x∈(-∞,+∞)且以π/2为最小正周期(1)求f(0)(2)求f(x)的解析式(3)已知f(α/4+π/12)=9/5求sinα的值
f(0)=3sin(w0+π/6),=3sin(π/6)=3/2
,π/2为最小正周期
∴根据公式T=2π/w ∴W=4
∴f(x)=3sin(4x+π/6)
第三问
f(a/4+π/12)=9/5
∴f(a/4+π/12)=3sin(4(a/4+π/12)+π/6)=3sin(a+π/3+π/6)=3cos(a)=9/5
所以cosa=3/5
根据公式cosa的平方=sina的平方=1
得sina=1-3/5的平方=+-4/5
谢谢采纳
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