y=-2cos(x/2+π/3),x∈[28π/5,a),若该函数是单调函数,求实数a的最大值.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 21:40:33
![y=-2cos(x/2+π/3),x∈[28π/5,a),若该函数是单调函数,求实数a的最大值.](/uploads/image/z/5124551-23-1.jpg?t=y%3D-2cos%28x%2F2%2B%CF%80%2F3%29%2Cx%E2%88%88%5B28%CF%80%2F5%2Ca%29%2C%E8%8B%A5%E8%AF%A5%E5%87%BD%E6%95%B0%E6%98%AF%E5%8D%95%E8%B0%83%E5%87%BD%E6%95%B0%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC.)
x)5J/֨7>ߠoS#1IyѽO>ٌO{m/uuAy{֥OMڱIOw-{c:[s ehjk|A~>e㓽3Y}/6.|>O@(irӷ@aE Nlx{)ª
F `DG 1" h
y=-2cos(x/2+π/3),x∈[28π/5,a),若该函数是单调函数,求实数a的最大值.
y=-2cos(x/2+π/3),x∈[28π/5,a),若该函数是单调函数,求实数a的最大值.
y=-2cos(x/2+π/3),x∈[28π/5,a),若该函数是单调函数,求实数a的最大值.
把28π/5代入得到角度为x/2+π/3=47π/15=3π+2π/15
由余弦函数图象知道在3π+2π/15到4π之间单调递增
所以x/2+π/3=4π x=22π/3
a=22π/3
已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos(x+y)+cos(x-y)】的值
y=cos(π/3-x)cos[π/2(x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性
y=2cos x (sin x+cos x)
y =(cos^2) x - sin (3^x),求y'
Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y)
证明COS(X+Y)COS(X-Y)=COS^2X-SIN^2Y
证明cos(x+y)cos(x-y)= cos^2(x)-sin^2(y)
sin(x+y)cosx+cos(x+y)sinx=1/3 x∈(3π/2,2π) 求cos(2x+π/4)
化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是:
y=(sin x + COS x)^2
y=(cos x-2)/(cos x-1)的值域
求函数y=cos(x-π/3),x∈[-π/2,π/2]的值域,
函数y=cos(x+π/3)的值域(其中x∈[-π/2,π/3])
y=cos^2 x-cos x +1的值域y=cos^2 x+cos x +1的值域,
求值域y=2sinx+cos^2x,x∈[π/6,2π/3)
y=2cos(2x+π/3)+1,x∈【0,π/2】的值域