已知函数f(x)=ax2-(a+2)x+lnx.(Ⅰ)当a=1时,求曲线y=f(x)在点(1,f(1))处的切线方程;(Ⅱ)当a>0时,函数f(x)在区间[1,e]上的最小值为-2,求a的取值范围;(Ⅲ)若对任意x1,x2∈(0,+
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![已知函数f(x)=ax2-(a+2)x+lnx.(Ⅰ)当a=1时,求曲线y=f(x)在点(1,f(1))处的切线方程;(Ⅱ)当a>0时,函数f(x)在区间[1,e]上的最小值为-2,求a的取值范围;(Ⅲ)若对任意x1,x2∈(0,+](/uploads/image/z/5126271-15-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dax2-%EF%BC%88a%2B2%EF%BC%89x%2Blnx%EF%BC%8E%EF%BC%88%E2%85%A0%EF%BC%89%E5%BD%93a%3D1%E6%97%B6%2C%E6%B1%82%E6%9B%B2%E7%BA%BFy%3Df%EF%BC%88x%EF%BC%89%E5%9C%A8%E7%82%B9%EF%BC%881%2Cf%EF%BC%881%EF%BC%89%EF%BC%89%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%EF%BC%9B%EF%BC%88%E2%85%A1%EF%BC%89%E5%BD%93a%EF%BC%9E0%E6%97%B6%2C%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E5%9C%A8%E5%8C%BA%E9%97%B4%5B1%2Ce%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA-2%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%9B%EF%BC%88%E2%85%A2%EF%BC%89%E8%8B%A5%E5%AF%B9%E4%BB%BB%E6%84%8Fx1%2Cx2%E2%88%88%EF%BC%880%2C%2B)
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已知函数f(x)=ax2-(a+2)x+lnx.(Ⅰ)当a=1时,求曲线y=f(x)在点(1,f(1))处的切线方程;(Ⅱ)当a>0时,函数f(x)在区间[1,e]上的最小值为-2,求a的取值范围;(Ⅲ)若对任意x1,x2∈(0,+
已知函数f(x)=ax2-(a+2)x+lnx.
(Ⅰ)当a=1时,求曲线y=f(x)在点(1,f(1))处的切线方程;
(Ⅱ)当a>0时,函数f(x)在区间[1,e]上的最小值为-2,求a的取值范围;
(Ⅲ)若对任意x1,x2∈(0,+∞),x1<x2,且f(x1)+2x1<f(x2)+2x2恒成立,求a的取值范围
已知函数f(x)=ax2-(a+2)x+lnx.(Ⅰ)当a=1时,求曲线y=f(x)在点(1,f(1))处的切线方程;(Ⅱ)当a>0时,函数f(x)在区间[1,e]上的最小值为-2,求a的取值范围;(Ⅲ)若对任意x1,x2∈(0,+
过程如图