分解因式:(a²+2a)²-2(a²+2a)-3
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分解因式:(a²+2a)²-2(a²+2a)-3
分解因式:(a²+2a)²-2(a²+2a)-3
分解因式:(a²+2a)²-2(a²+2a)-3
解
(a²+2a)²-2(a²+2a)-3——将a²+2a看成一个整体,十字相乘
=[(a²+2a)-3][(a²+2a)+1]
=(a²+2a-3)(a²+2a+1)
=(a+3)(a-1)(a+1)²
令u=a^+2a,得u^-2u-3=0,解出u1.u2在代入a^+2a,就可以了