分解因式:x²(x-1)-2x(x²-2x+1)的分解过程
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/26 23:19:42
![分解因式:x²(x-1)-2x(x²-2x+1)的分解过程](/uploads/image/z/5150430-54-0.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%3Ax%26%23178%3B%28x-1%29-2x%28x%26%23178%3B-2x%2B1%EF%BC%89%E7%9A%84%E5%88%86%E8%A7%A3%E8%BF%87%E7%A8%8B)
x){b⧳Qb6IE/biX-X I&D*ki_\gu
CVbX
U GR;u] :zN@H408JbB5t+i|`DdC\dD
分解因式:x²(x-1)-2x(x²-2x+1)的分解过程
分解因式:x²(x-1)-2x(x²-2x+1)的分解过程
分解因式:x²(x-1)-2x(x²-2x+1)的分解过程
x²(x-1)-2x(x²-2x+1)=x²(x-1)-2x(x-1)²
=(x-1)(x²-2x)
=x(x-1)(x-2)
x²(x-1)-2x(x²-2x+1)
=x²(x-1)-2x(x-1)²
=(x-1)[x²-2x(x-1)]
=(x-1)(﹣x²+2x)
=﹣x(x-1)(x-2)
x²(x-1)-2x(x²-2x+1)
=x²(x-1)-2x(X-1)²
=X(X-1)[x-2(x-1)]
=x(x-1)(x-2x+2)
=x(x-1)(2-x)
原式=x²(x-1)-2x(x-1)²=x(x-1)(x-2x﹢2)=x(x-1)(2-x)