作业帮matlab二元函数请问各路大神,MatLab中我求二元二次函数,怎么会这样的结果,看不懂啊,>> [xc,yc]=solve('2*(xa-xc)^2+2*(ya-yc)^2=(xb-xa)^2+(yb-ya)^2','2*(xb-xc)^2+2*(yb-yc)^2=(xb-xa)^2+(yb-ya)^2')xc =xc-yb+ycxc+yb-yc-i*((xc+i*(y
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![matlab二元函数请问各路大神,MatLab中我求二元二次函数,怎么会这样的结果,看不懂啊,>> [xc,yc]=solve('2*(xa-xc)^2+2*(ya-yc)^2=(xb-xa)^2+(yb-ya)^2','2*(xb-xc)^2+2*(yb-yc)^2=(xb-xa)^2+(yb-ya)^2')xc =xc-yb+ycxc+yb-yc-i*((xc+i*(y](/uploads/image/z/5169701-29-1.jpg?t=matlab%E4%BA%8C%E5%85%83%E5%87%BD%E6%95%B0%E8%AF%B7%E9%97%AE%E5%90%84%E8%B7%AF%E5%A4%A7%E7%A5%9E%2CMatLab%E4%B8%AD%E6%88%91%E6%B1%82%E4%BA%8C%E5%85%83%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%2C%E6%80%8E%E4%B9%88%E4%BC%9A%E8%BF%99%E6%A0%B7%E7%9A%84%E7%BB%93%E6%9E%9C%2C%E7%9C%8B%E4%B8%8D%E6%87%82%E5%95%8A%2C%3E%3E+%5Bxc%2Cyc%5D%3Dsolve%28%272%2A%28xa-xc%29%5E2%2B2%2A%28ya-yc%29%5E2%3D%28xb-xa%29%5E2%2B%28yb-ya%29%5E2%27%2C%272%2A%28xb-xc%29%5E2%2B2%2A%28yb-yc%29%5E2%3D%28xb-xa%29%5E2%2B%28yb-ya%29%5E2%27%29xc+%3Dxc-yb%2Bycxc%2Byb-yc-i%2A%28%28xc%2Bi%2A%28y)
matlab二元函数请问各路大神,MatLab中我求二元二次函数,怎么会这样的结果,看不懂啊,>> [xc,yc]=solve('2*(xa-xc)^2+2*(ya-yc)^2=(xb-xa)^2+(yb-ya)^2','2*(xb-xc)^2+2*(yb-yc)^2=(xb-xa)^2+(yb-ya)^2')xc =xc-yb+ycxc+yb-yc-i*((xc+i*(y
matlab二元函数
请问各路大神,MatLab中我求二元二次函数,怎么会这样的结果,看不懂啊,
>> [xc,yc]=solve('2*(xa-xc)^2+2*(ya-yc)^2=(xb-xa)^2+(yb-ya)^2','2*(xb-xc)^2+2*(yb-yc)^2=(xb-xa)^2+(yb-ya)^2')
xc =
xc-yb+yc
xc+yb-yc
-i*((xc+i*(yb-yc))*xc-xc^2+yb*yc-yc^2-yb*ya+ya*yc)/(yb-yc)
i*((xc-i*(yb-yc))*xc-xc^2+yb*yc-yc^2-yb*ya+ya*yc)/(yb-yc)
yc =
ya+xc-yc
-ya+yc+xc
xc+i*(yb-yc)
xc-i*(yb-yc)
matlab二元函数请问各路大神,MatLab中我求二元二次函数,怎么会这样的结果,看不懂啊,>> [xc,yc]=solve('2*(xa-xc)^2+2*(ya-yc)^2=(xb-xa)^2+(yb-ya)^2','2*(xb-xc)^2+2*(yb-yc)^2=(xb-xa)^2+(yb-ya)^2')xc =xc-yb+ycxc+yb-yc-i*((xc+i*(y
没错呀.结果是时域和代数.就是不知道a和b的值域.
没错呀。结果是时域和代数。就是不知道a和b的值域。